zoj 1057 - 行者无疆 始于足下 - 行走,思考,在路上

zoj 1057

xiaohanyu posted @ Sun, 21 Mar 2010 10:54:38 +0800 in Algorithm with tags ZOJ , 2252 readers

编程还是很菜。很简单的题,基本的输入输出格式弄了很久。没脸见人了。zoj的选拔标准有变,我看能否在两个月之内拿下三百道题。还得把lpi考掉,恐怕要顺延到暑假了。加油加油。

晚上的计算机体系结构实验搞的很崩溃,硬件的课程,该怎么办呢。也不知道对自己以后能有多大的帮助,目前策略是得过且过……组了个队,同组的竟然是个04级的,令我颇为差异。看来,计算机的毕业也不是那么简单。

is-programmer博客系统越来越强大了。最近加入的代码高亮真的是非常的棒!赞!

顺便,86版五笔初有小成,逐渐转移到五笔输入法,效率之上的生活! 

#include <iostream>
using namespace std;

int main(int argc, char *argv[])
{
    int cases;

    const int max_size = 20;

    int a[max_size];
    int b[max_size];

    int sum_a;
    int sum_b;

    int times = 0;
    while (cin >> cases)
    {
        if (cases == 0)
        {
            break;
        }
        else
        {
            times++;
            
            if (times >= 2)
            {
                cout << endl << endl;
            }
        }
        
        sum_a = sum_b = 0;

        for (int i = 0; i < cases; ++i)
        {
            cin >> a[i];
        }

        for (int i = 0; i < cases; ++i)
        {
            cin >> b[i];
        }

        for (int i = 0; i < cases; ++i)
        {
            if (a[i] == 1 && b[i] == 2)
            {
                sum_a += 6;
            }
            else if (a[i] == 2 && b[i] == 1)
            {
                sum_b += 6;
            }
            else if (a[i] - b[i] == 1)
            {
                sum_b += a[i] + b[i];
            }
            else if (b[i] - a[i] == 1)
            {
                sum_a += a[i] + b[i];
            }
            else if (a[i] - b[i] >= 2)
            {
                sum_a += a[i];
            }
            else if (b[i] - a[i] >= 2)
            {
                sum_b += b[i];
            }
            else;
        }

        cout << "A has " << sum_a << " points. B has " << sum_b << " points.";
    }

    return 0;
}

 


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